(12x^2)-228x+704=0

Solution for (12x^2)-228x+704=0 equation:

(12x^2)-228x+704=0

a = 12; b = -228; c = +704;
Δ = b2-4ac
Δ = -2282-4·12·704
Δ = 18192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18192}=\sqrt{16*1137}=\sqrt{16}*\sqrt{1137}=4\sqrt{1137}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-228)-4\sqrt{1137}}{2*12}=\frac{228-4\sqrt{1137}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-228)+4\sqrt{1137}}{2*12}=\frac{228+4\sqrt{1137}}{24}
$